Swap Two Number Program in C#

Swap Two Numbers Program in C#

There are two method to swap any two numbers, using third variable and without using third variable. here we write this code using third variable and without using third variable.

using System;  
  public class Swap_Demo  
   {  
     public static void Main(string[] args)  
      {  
       int  a=10, b=20, temp;            
       Console.WriteLine("Before swap a= "+a+" b= "+b);    
       temp=a;  //temp=10      
       a=b;  //a=20      
       b=temp;  //b=10   
       Console.Write("After swap a= "+a+" b= "+b);       
      }  
  }

Before Swap a= 10 b=20
After Swap a= 20 b=10

using System;  

  public class Swap_Demo  
  {  
  public static void Main(string[] args)  
  {  
   int  a=10, b=20;            
   Console.WriteLine("Before swap a= "+a+" b= "+b);    
   a=a+b; //a=30 (10+20)      
   b=a-b; //b=10 (30-20)      
   a=a-b; //a=20 (30-10)   
   Console.Write("After swap a= "+a+" b= "+b);       
  }  
  }

Before Swap a= 10 b=20
After Swap a= 20 b=10

using System;  
 public class Swap_Demo  
 {  
 public static void Main(string[] args)  
 {  
 int a, b;          
 Console.Write("\nInput the First Number: ");
 a = int.Parse(Console.ReadLine());
 Console.Write("\nInput the Second Number: ");
 b = int.Parse(Console.ReadLine());      
 Console.WriteLine("Before swap a= "+a+" b= "+b);    
 a=a+b; //a=30 (10+20)      
 b=a-b; //b=10 (30-20)      
 a=a-b; //a=20 (30-10)   
 Console.Write("After swap a= "+a+" b= "+b);       
 }  
}

Input the First Number: 10
Input the Second Number: 20
Before Swap a= 10 b=20
After Swap a= 20 b=10