Convert Hexadecimal to Binary in C
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Convert Hexadecimal to Binary Program in C
In this types of program we takes a Hexadecimal number as input and converts it into binary number. To convert Hexadecimal to binary number first accept binary as a input then convert into equivalent Hexadecimal number
- Take a binary number as input.
- Make Pair of 4 digits binary number.
- Convert these three binary pair number into equivalent Decimal number.
- Combind these decimal number.
- Done
Programming Steps to Convert Hexadecimal to Binary
- Take a Hexadecimal number as input.
- Print the binary value of each digit of a Hexadecimal number. Use switch statement and while loop to do this.
Convert Hexadecimal to Binary in C
#include<stdio.h>
#include<conio.h>
#define MAX 1000
void main()
{
char binary_number[MAX], hexa[MAX];
long int i = 0;
clrscr();
printf("Enter the value for Hexadecimal ");
scanf("%s", hexa);
printf("\n Equivalent Binary value: ");
while (hexa[i])
{
switch (hexa[i])
{
case '0':
printf("0000"); break;
case '1':
printf("0001"); break;
case '2':
printf("0010"); break;
case '3':
printf("0011"); break;
case '4':
printf("0100"); break;
case '5':
printf("0101"); break;
case '6':
printf("0110"); break;
case '7':
printf("0111"); break;
case '8':
printf("1000"); break;
case '9':
printf("1001"); break;
case 'A':
printf("1010"); break;
case 'B':
printf("1011"); break;
case 'C':
printf("1100"); break;
case 'D':
printf("1101"); break;
case 'E':
printf("1110"); break;
case 'F':
printf("1111"); break;
case 'a':
printf("1010"); break;
case 'b':
printf("1011"); break;
case 'c':
printf("1100"); break;
case 'd':
printf("1101"); break;
case 'e':
printf("1110"); break;
case 'f':
printf("1111"); break;
default:
printf("\n Invalid hexa digit %c ", hexa[i]);
return 0;
}
i++;
}
getch();
}
Output 1
Please Enter any Hexadecimal Number: E1 Equivalent Binary Value 11100001
Output 2
Please Enter any Hexadecimal Number: D2 Equivalent Binary Value 11010010
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