# Convert Hexadecimal to Binary in C

## Convert Hexadecimal to Binary Program in C

In this types of program we takes a Hexadecimal number as input and converts it into binary number. To convert Hexadecimal to binary number first accept binary as a input then convert into equivalent Hexadecimal number

• Take a binary number as input.
• Make Pair of 4 digits binary number.
• Convert these three binary pair number into equivalent Decimal number.
• Combind these decimal number.
• Done

### Programming Steps to Convert Hexadecimal to Binary

• Take a Hexadecimal number as input.
• Print the binary value of each digit of a Hexadecimal number. Use switch statement and while loop to do this.

## Convert Hexadecimal to Binary in C

```#include<stdio.h>
#include<conio.h>
#define MAX 1000

void main()
{
char binary_number[MAX], hexa[MAX];
long int i = 0;
clrscr();

printf("Enter the value for Hexadecimal ");
scanf("%s", hexa);
printf("\n Equivalent Binary value: ");
while (hexa[i])
{
switch (hexa[i])
{
case '0':
printf("0000"); break;
case '1':
printf("0001"); break;
case '2':
printf("0010"); break;
case '3':
printf("0011"); break;
case '4':
printf("0100"); break;
case '5':
printf("0101"); break;
case '6':
printf("0110"); break;
case '7':
printf("0111"); break;
case '8':
printf("1000"); break;
case '9':
printf("1001"); break;
case 'A':
printf("1010"); break;
case 'B':
printf("1011"); break;
case 'C':
printf("1100"); break;
case 'D':
printf("1101"); break;
case 'E':
printf("1110"); break;
case 'F':
printf("1111"); break;
case 'a':
printf("1010"); break;
case 'b':
printf("1011"); break;
case 'c':
printf("1100"); break;
case 'd':
printf("1101"); break;
case 'e':
printf("1110"); break;
case 'f':
printf("1111"); break;
default:
printf("\n Invalid hexa digit %c ", hexa[i]);
return 0;
}
i++;
}
getch();
}
```

## Output 1

```Please Enter any Hexadecimal Number: E1
Equivalent Binary Value 11100001
```

## Output 2

```Please Enter any Hexadecimal Number: D2
Equivalent Binary Value 11010010
```