Convert Decimal to Hexadecimal Program in C++

C++ program to Convert Decimal to Hexadecimal

To convert binary to hexadecimal in C++ Program, we have to ask to the user to enter any number in binary to convert it into hexadecimal, then display the equivalent hexadecimal value on the screen.

Binary Numbers: Binary number Base is 2 because Binary numbers is 0 and 1. Examples of Decimal Number is 110, 111, 1011, 1111, 1010 etc

Hexadecimal Numbers: Hexadecimal number Base is 16 because Hexadecimal represent value of 0 to 9 and A to F. Examples of Hexadecimal Number is 1E, F, 3E8, 5A... etc.

Input Binary Number : 1011
Euivalent Hexadecimal Number : B

Input Binary Number : 11011
Euivalent Hexadecimal Number : 1B

Input Binary Number : 11110
Euivalent Hexadecimal Number : 1E

Algorithom to Convert Binary to Hexadecimal

• Divide the number by 16.
• Get the integer quotient for the next iteration.
• Get the remainder for the hex digit.
• Repeat the steps until the quotient is equal to 0.

#include<iostream.h>
#include<conio.h>
#define 1000

void main()
{
        char binnum[MAX], hexa[MAX];
        int temp;
        long int i=0,j=0;
        clrscr();
        cout<<"Enter any Binary Number: ";
        cin>>binnum;
        while(binnum[i])
        {
          binnum[i] = binnum[i] -48;
          ++i;
        }
        --i;
        while(i-2>=0)
        {
          temp =  binnum[i-3] *8 + binnum[i-2] *4 +  binnum[i-1] *2 + binnum[i] ;
          if(temp > 9)
          hexa[j++] = temp + 55;
           else
            hexa[j++] = temp + 48;
            i=i-4;
        }
        if(i ==1)
          hexa[j] = binnum[i-1] *2 + binnum[i] + 48 ;
        else if(i==0)
          hexa[j] =  binnum[i] + 48 ;
        else
         --j;
        cout<<"Equivalent Hexadecimal Number is: \n";
        while(j>=0)
        {
         cout<<hexa[j--];
        }
getch();
}

Enter any Binary Number : 10011
Equivalent Hexadecimal Number is: 13