Convert Hexadecimal to Binary Program in C++

C++ program to Convert Hexadecimal to Binary

To convert hexadecimal number to binary number in C++ programming, We have to ask to the user to enter the hexadecimal number to convert it into binary number to display the equivalent value in binary format on screen.

0=0000
1=0001
2=0010
3=0011
4=0100
5=0101
6=0110
7=0111
8=1000
9=1001
A=1010 (decimal 10)
B=1011 (decimal 11)
C=1100 (decimal 12)
D=1101 (decimal 13)
E=1110 (decimal 14)
F=1111 (decimal 15)

Input Hexadecimal Number : F
Euivalent Binary Number : 1111

Input Hexadecimal Number : 3F
Euivalent Binary Number : 111111

Input Hexadecimal Number : 2A
Euivalent Binary Number : 101010

#include<iostream.h>
#include<conio.h>

void main()
{
	clrscr();
	long int i=0;
	char binnum[100], hexdec[100];
	cout<<"Enter any Hexadecimal Number: ";
	cin>>hexdec;
	cout<<"\nEquivalent Binary Value is: ";
	while(hexdec[i])
	{
		switch(hexdec[i])
		{
			case '0' : cout<<"0000";
				break;
			case '1' : cout<<"0001";
				break;
			case '2' : cout<<"0010";
				break;
			case '3' : cout<<"0011";
				break;
			case '4' : cout<<"0100";
				break;
			case '5' : cout<<"0101";
				break;
			case '6' : cout<<"0110";
				break;
			case '7' : cout<<"0111";
				break;
			case '8' : cout<<"1000";
				break;
			case '9' : cout<<"1001";
				break;
			case 'A' : cout<<"1010";
				break;
			case 'B' : cout<<"1011";
				break;
			case 'C' : cout<<"1100";
				break;
			case 'D' : cout<<"1101";
				break;
			case 'E' : cout<<"1110";
				break;
			case 'F' : cout<<"1111";
				break;
			case 'a' : cout<<"1010";
				break;
			case 'b' : cout<<"1011";
				break;
			case 'c' : cout<<"1100";
				break;
			case 'd' : cout<<"1101";
				break;
			case 'e' : cout<<"1110";
				break;
			case 'f' : cout<<"1111";
				break;
			default : cout<<"\nInvalid Hexadecimal Digit "<<hexdec[i];
	}
   i++;
  }
 getch();
}

Enter any Hexadecimal Number: 2C
Equivalent Binary Value is: 101100